Question 677433
{{{sqrt(x-3) + 5 = x}}}
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{{{sqrt(x-3) = x-5}}}
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{{{sqrt(x-3)^2 = (x-5)^2}}}
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x-3 = {{{x^2 - 10x + 25}}}
0 = {{{x^2 - 10x + 25 -x + 3}}}
0 = {{{x^2 - 11x + 28}}}
0 = (x-4)(x-7)
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x-4=0, so {{{highlight_green(x=4)}}}
AND
x-7=0, so {{{highlight_green(x=7)}}}
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