Question 677368
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Let *[tex \LARGE p_1] represent the first number, and *[tex \LARGE p_2] represent the second number, then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ p_1\ +\ 2p_2\ =\ 48]


Hence, *[tex \LARGE p_1\ =\ 48\ -\ 2p_2]


So *[tex \LARGE y\ =\ p_2(48\ -\ 2p_2)\ =\ -(2p_2)^2\ -\ 48p_2]


Take the first derivative, set it equal to zero.  Solve to get the ordinate of the extreme point.


Take the second derivative and evaluate it at the ordinate of the extreme point.  If positive, the extreme is a minimum, if negative, the extreme is a maximum.
 

John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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