Question 677384
{{{x^9-y^15}}}


{{{(x^3)^3-(y^5)^3}}}


{{{(x^3-y^5)((x^3)^2+x^3y^5+(y^5)^2)}}} Use the difference of cubes factoring rule.


{{{(x^3-y^5)(x^6+x^3y^5+y^(10))}}}


So the final answer is {{{(x^3-y^5)(x^6+x^3y^5+y^(10))}}}