Question 61131
y=2x^2-8x. Find the y-intercepts and any x-intercepts.
To find the y-intercept, let x=0 and solve for y.
{{{y=2(0)^2-8(0)}}}
{{{y=2(0)-0}}}
{{{y=0-0}}}
{{{y=0}}}
The y-intercept is (0,0)  This is where the graph would cross the y-axis.
:
To find the x intercepts, let y=0 and solve for x.
{{{0=2x^2-8x}}}  Factor the GCF, 2x out.
0=2x(x-4)
2x=0 and x-4=0
2x/2=0/2 and x-4+4=0+4
x=0 and x=4
The x-intercepts are (0,0) and (4,0)
Notice that the origin (0,0) is both an x-intercept and a y-intercept.
Here's what the graph looks like:
{{{graph(300,200,-5,5,-10,10,2x^2-8x)}}}
Happy Calculating!!!