Question 677079
Let the speed of helicopter = h m/h
and speed of wind = w m/h

When flying with the direction of wind, the effective speed = (h + w) m/h
In one and half (1 1/2 = 3/2) hours, the helicopter will fly = (h + w) * 3/2

Therefore, (h + w) * 3/2 = 300
or, (h + w) * 3 = 300 * 2
or, (h + w) * 3 / 3 = 600 / 3
or, h + w = 200 ... ... ... (1)

When flying against the direction of wind, the effective speed = (h - w) m/h
In 3 hours, the helicopter will fly = (h - w) * 3

Therefore, (h - w) * 3 = 300
or, (h - w) * 3 / 3 = 300 / 3
or, h - w = 100 ... ... ... (2)

By adding (1) and (2),  2h = 300
Therefore, h = 300 / 2 = 150 m/h

From (1), 150 + w = 200
or, w = 200 - 150
Therefore, w = 50 m/h

So, the speed of helicopter = 150 m/h and that of wind = 50 m/h