Question 61131
Given y = 2x^2 – 8x              (1)

To find the “y” intercepts, we substitute for x = 0 in equation (1), we get

y = 0

The y intercepts is y = 0.

To find the “x” intercepts, we substitute for y = 0 in equation (1), we get

2x^2 – 8x = 0

2x^2 = 8x

Divide the above equation by 2x, we get

x = 4
 
The “x” intercepts is x = 4.

Hence the y intercepts is 0 and the x intercepts is 4.