Question 676784
x + 2y = 5
rearranged as
2y = -x + 5
y = {{{(-1/2)x + (5/2)}}} --> linear equation for this line
...
kx + 3y = 3
rearranged as
3y = -kx + 3
y = {{{(-k/3)x + (3/3)}}} --> linear equation for this line
...
Since the slopes cannot be the same, solve for k when they are set equal
{{{(-1/2)=(-k/3)}}}
cross multiply
-3 = -2k
k = {{{3/2}}} when the slopes are the same.
therefore,
{{{k<>3/2}}}
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