Question 676841
{{{(t/(t-3)) + (3/(t+3)) = (18/(t^2-9))}}}
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Multiply the entire equation by (t^2-9) which is (t-3)(t+3)
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{{{t(t+3) + 3(t-3) = 18}}}
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{{{t^2 + 3t + 3t - 9 = 18}}}
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{{{t^2 + 6t - 9 - 18 = 0}}}
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{{{t^2 + 6t -27}}}=0
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(t-3)(t+9)=0
t = 3
t = -9
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