Question 676607

{{{(6x+7)/(4x-12)}}}... the restricted values will be all values for what {{{4x-12}}} is equal to zero because {{{4x-12}}} is denominator and to divide by zero doesn't make sense

set {{{4x-12}}} equal to zero and find {{{x}}}

{{{4x-12=0}}}

{{{4x=12}}}

{{{x=12/4}}}

{{{x=3}}}.......all real numbers except {{{x=3}}}

so, answer is  D. {{{x=3}}}