Question 676511
1st throw: 1/6 probability A wins
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2nd: 1- 1/6 = 5/6
5/6 * 2/6 = 5/18 prob B wins
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3rd 1-(1/6 + 5/18)=5/9
5/9 * 3/6 = 5/18 prob A wins
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4th 1-(1/6 + 5/18 + 5/18)=5/18
5/18 * 4/6 =5/27 prob B wins
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5th 1-(1/6 + 5/18 + 5/18 + 5/27)=5/54
5/54 * 5/6 = 25/324 Prob A wins
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1-(1/6 + 5/18 + 5/18 + 5/27 + 25/324)=5/324 prob B wins.
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1/6 + 5/18 + 25/324 = 169/324 the total probabilities of A’s success.
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Ed