Question 676476
sin^2x* cosx-sinx=0

Solution:

Sin^2x * Cosx - Sinx = 0 -------->(1)

Taking Sinx the common from (1)

Sinx(Sinx * Cosx - 1) = 0

If two factors are equal to zero then each factor will equal to be zero.

i.e.

Sinx = 0 ---------> (2)

and

Sinx * Cosx -1 = 0 -------->(3)

From (2)

x = Sin^-1(0)

or 

x = 0

From (3)

Sinx * Cosx = 1

or

Sinx = 1/Cosx

or

x = Sin^-1(1/Cosx)

or

x = Cos^-1(1/Sinx)

Thus

x = 0 , Sin^-1(1/Cosx)OR Cos^-1(1/Sinx)


Hope the answer your question
Regards
Khurshidi
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