Question 676411
{{{(v^2-3v-54)/(v+4)}}}
...
(v+4) goes into {{{v^2-3v}}}: v
to get
{{{v^2 + 4v}}}
subtracting
{{{v^2 - v^2 - 3v - 4v}}}
yielding
-7v
...
(v+4) goes into -7v - 54: -7
to get
-7v - 28
subtracting
-7v - -7v - 54 - - 28
yielding
-26 as the remainder
...
{{{(v^2-3v-54)/(v+4) = v-7}}}{{{(-26)/(v-7)}}}

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