Question 676059
how do you solve log base 4 of (x+3)+log base 4 of (x-3)=2
log4(x+3)+log4(x-3)=2
log4[(x+3)(x-3)]=2
convert to exponential form: base(4) raised to log of number(2)=number[(x+3)(x-3)]
2^4=(x+3)(x-3)=16
x^2-9=16
x^2=25
x=-5 (reject, (x+3)>0)
x=5