Question 675774
v=(4,2) Directrix : y=5
This is a parabola that opens downwards.
Its standard form of equation: (x-h)^2=-4p(y-k), (h,k)=(x,y) coordinates of vertex
given coordinates of the vertex:(4,2)
axis of symmetry: x=2
focus:(4,-1) (3 units below vertex on the axis of symmetry)
p=3 (distance from directrix to vertex on the axis of symmetry)
4p=12
equation:
(x-4)^2=-12(y-2)

note:The directrix is always located on the opposite side the parabola is facing and the focus is on the side the parabola is facing, both p-distance from the vertex on the axis of symmetry.