Question 61086
Help Please! Find the exact an approximate solution. Find two positive real numbers that differ by one and have a product of one. 
LET ONE NUMBER = X
OTHER NUMBER = X-1
PRODUCT = X(X-1)=1
X^2-X=1
X^2-X-1=0.....COMPARING WITH AX^2+BX+C=0...A=1...B=-1....C=-1
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-(-1) +- sqrt( (-1)^2-4*1*(-1) ))/(2*1) }}}
{{{x = (1 +- sqrt( 1+4 ))/(2) }}}
{{{x = (1 +- sqrt( 5 ))/(2) }}}
SINCE POSITIVE NUMBERS ARE ASKED FOR THEY ARE 
[1+SQRT(5)]/2 AND [1+SQRT(5)]/2 -1..OR ....[SQRT(5)-1]/2