Question 676167
{{{ ( 3 - 2*i ) / ( 1 + 2*i ) }}}
{{{ (( 3 - 2*i ) / ( 1 + 2*i ))*( 1 - 2*i ) / ( 1 - 2*i ) }}}
Note that I am just multiplying by {{{ a/a = 1 }}}
{{{ (( 3 - 2*i )*( 1 - 2*i )) / (( 1 - 2*i )*( 1 + 2i )) }}}
{{{ (( 3 - 2*i )*( 1 - 2*i )) / ( 1 - 4*(-1)) }}}
{{{ (( 3 - 2*i )*( 1 - 2*i )) / 5 }}}
{{{ ( 3 - 2*i - 6*i + 4*(-1) ) / 5 }}}
{{{ ( -1 - 8*i ) / 5 }}}
{{{ -1/5 - (8/5)*i }}}
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I should be able to check by making it equal to
the original expression
{{{ ( 3 - 2*i ) / ( 1 + 2*i ) = ( -1 - 8*i ) / 5 }}}
{{{ (5*( 3 - 2*i )) / ( 1 + 2*i ) =  -1 - 8*i  }}} 
{{{ ( 15 - 10*i ) / ( 1 + 2*i ) = -1 - 8*i }}}
{{{ 15 - 10*i = -1*(1 + 2*i )*( 1 + 8*i ) }}}
{{{ 15 - 10*i = -1*( 1 + 2*i + 8*i + 16*(-1) ) }}}
{{{ 15 - 10*i = -1 - 2*i - 8*i - (-16) }}}
{{{ 15 - 10*i = 15 - 10*i }}}
OK