Question 676000
A man has 26 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 485 cents, how many dimes and quarters does he have?
.
Let x = number of dimes
then
26-x = number of quarters
.
10x + 25(26-x) = 485
10x + 650-25x = 485
650-15x = 485
-15x = -165
x = -165/(-15)
x = 11 (dimes)
.
quarters:
25-11 = 14