Question 675756
To "undo" the square, use the square root (on both sides)
{{{sqrt(y-2/3)^2)}}} = +/- {{{sqrt(4/9)}}}
...
{{{y-(2/3)}}} = +/- {{{sqrt(4/9)}}}
...
y - {{{2/3}}} = +/- 2/3
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Add {{{2/3}}} to both sides to isolate y
{{{highlight_green(y = (2/3) +- (2/3))}}}
...
Which can be expanded as
y = {{{2/3 + 2/3 = highlight_green(4/3)}}}
AND
y = {{{2/3 - 2/3 = highlight_green(0)}}}
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