Question 675751
Let {{{ y }}} = Todd's age now
{{{ 2y }}} = Chris's age now
{{{ y + x }}} = Todd's age in {{{ x }}} years
{{{ 2y + x }}} = Chris's age in {{{ x }}} years
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given:
{{{ 2y + x = (3/2)*( y + x ) }}}
{{{ 2*( 2y + x ) = 3*( y + x ) }}}
{{{ 4y + 2x = 3y + 3x }}}
{{{ 4y - 3y = 3x - 2x }}}
{{{ y = x }}}
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Todd is presently {{{ x }}} years old
check answer:
Todd is {{{ x }}} now
Chris is {{{ 2x }}}
In {{{ x }}} years, Todd is {{{ x + x = 2x }}}
In {{{ x }}} years, Chris is {{{ 2x + x = 3x }}}
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{{{ 3x = (3/2)*2x }}}
{{{ 6x = 6x }}}
OK