Question 675752
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Hi
h= -16t^2+80t+48 = 0   (object hitting the ground)
 -16t^2+80t+48 = 0
 16t^2-80t-48 = 0
 t^2-5t-3 = 0
{{{t = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{t = (5 +- sqrt( 37 ))/(2) }}} ||Positive value only for unit measure
0r
 -16(t-5/2)^2 + 100 + 48 = 0
 -16(t-5/2)^2 + 148 = 0
     t = 5/2 ± sqrt(148/16)
     t = 5/2 ± sqrt(37)/2