Question 675746
{{{4x < 16/(x+3)}}}
...
Multiply both sides by (x+3)
{{{4x(x+3) < (16/cross((x+3)))(cross(x+3))}}}
4x(x+3) < 16
4x(x+3) - 16 < 0
...
Distribute the 4x
{{{4x^2 + 12x - 16 < 0}}}
{{{4(x^2 + 3x - 4) < 0}}}
4(x-1)(x+4) < 0
OR
{{{4x^2+12x-16<0}}}
{{{0<-4x^2 - 12x + 16}}}
{{{0<-4(x^2+3x-4)}}}
{{{0<-4(x+4)(x-1)}}}
...

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