Question 675590
Anne and Nancy use a metal alloy that is 17.3% copper to make jewelry. How many ounces of a 17% alloy must be mixed with a 18% alloy to form 80 ounces of the desired alloy?
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let x=amt of 17% alloy to be mixed
80-x=amt of 18% alloy to be mixed
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17%x+18%(80-x)=17.3%*80
.17x+14.4-.18x=13.84
.01x=.56
x=56
80-x=24
amt of 17% alloy to be mixed=56 oz
amt of 18% alloy to be mixed=24 oz