Question 675375
|2x+1| < 7
...
2x + 1 < 7 
2x < 7-1
2x < 6
2x < 6
{{{highlight_green(x<3)}}}
AND
2x+1 > -7
2x > -7 + 1
2x > - 6
x > -3
{{{highlight_green(x>-3)}}}
...
{{{highlight(-3 < x < 3)}}} 
.....................
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