Question 675340


{{{Shirley  = x}}}
{{{Mike = x+2}}}...........

{{{8}}} years ago:

{{{Shirley= x-8 }}}
{{{ Mike = 2(x-8)}}}
   
{{{x-8 = 2(x-8)}}}...solve for {{{x}}}

{{{x-8 = 2x-16}}}

{{{16-8 = 2x-x}}}

{{{x = 8}}}...........Shirley's age 

{{{ x+2=10}}}....Mike's age