Question 670441
{{{sqrt((bx^2-c)/(4a^2+a))}}}
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{{{sqrt(bx^2-c)/sqrt(4a^2+a)}}}
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{{{(sqrt(bx^2-c)/sqrt(4a^2+a))(sqrt(4a^2+a)/sqrt(4a^2+a))}}}
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denominator
{{{sqrt((4a^2 + a)(4a^2 + a)) =  4a^2+a}}}
numerator
{{{sqrt(bx^2-c)sqrt(4a^2+a) = sqrt((bx^2-c)(4a^2+a))}}}
{{{sqrt(4a^2bx^2 + abx^2 - c4a^2 - ca)}}}
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{{{sqrt(4a^2bx^2+abx^2-4a^2c - ac)/(4a^2a+a) = (2ax*x*a*2sqrt(b+ab-c-ac)/(4a^2+a) )=( 4a^2x^2sqrt(b+ab-c-ca)/(a(4a+1))) = (4ax^2sqrt(b+ab-a-2))/(4a+1)}}}
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