Question 674579
The expressions will be undefined where 0 is the denominator
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1)
{{{x^2 + 4 = 0}}}
{{{x^2 = -4}}}
{{{sqrt(x^2)}}} = +/- {{{sqrt(-4)}}}
x = +/- {{{sqrt(4*-1)}}}
x = +/- 2i
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2)
{{{x^2-9x+20 = 0}}}
{{{(x-5)(x-4) = 0}}}
x = 5 and 4
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3)
(x-7)(x-9)=0
x = 7 and 9
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