Question 675254
 2^(8+4x) = 1/16
:
Actually {{{1/16 = 2^-4}}} 
so we have an equiv equation of:
{{{2^((8+4x)) = 2^-4}}}
It the bases are equal, the exponents are equal, so we have:
8 + 4x = -4
4x = -4 - 8
4x = -12
x = -12/4
x = -3
:
:
Check this in your calc: enter 2^(8+4(-3)) results: .0625 which is 1/16