Question 675148
{{{sqrt(49) = sqrt(7*7) = 7}}}
...
{{{root(3,-27) = root(3,-1*27) = root(3, -1*3*3*3) = 3root(3,-1)}}}
...
{{{sqrt(4x^6) = sqrt(2*2*x^3*x^3) = 2x^3}}}
...
{{{sqrt(28) = sqrt(4*7) = sqrt(2*2*7) = 2sqrt(7)}}}
...
{{{sqrt(27a^5) = sqrt(3*3*3*a^2*a^2*a) = 3a^2sqrt(3a)}}}
.....................
Delighted to help.
-Reading Boosters
Website: www.MyHomeworkAnswers.com
Wanting for others what we want for ourselves.