Question 675201


{{{log(x^2 - 2x + 1) > log(25)}}}

{{{log((x-1) ^2 ) > log(5^2)}}}

{{{2log(x-1) > 2log(5)}}}

{{{log(x-1) > log(5)}}}

The log is an increasing function, so if {{{log (x-1) > log(5)}}} then {{{x-1}}} 

should be greater than {{{5}}}. 

So {{{x-1 > 5}}}, which means {{{x > 6}}}.

your answer is: (d) {{{x > 6}}}