Question 674922
x-2y=0
3x-y^2=0
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solve the first equaiton for x
x = 2y
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Plug this x into the second equation
3(2y) - y^2 = 0
6y - y^2 = 0
-y^2 + 6y = 0
-y(y-6) = 0
(y-6) = 0
{{{highlight_green(y = 6)}}}
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Plug y back into the first equation

x-2(6) = 0
x - 12 = 0
{{{highlight_green(x=12)}}}
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