Question 674689
Two boys, Shawn and Curtis, went for a walk.
 Shawn began walking 20 seconds earlier than Curtis.
 Shawn walked at a speed of 5 feet per second.
 Curtis walked at a speed of 6 feet per second.
 For how many seconds had Shawn been walking at the moment when the two boys had walked exactly the same distance?
:
let t = walking time of S
then
(t-20) = walking time of C; (started 20 sec after S)
:
Write a distance equation; dist = speed * time
:
5t = 6(t-20)
5t = 6t - 120
120 = 6t - 5t
t = 120 seconds, is S's walking time
:
:
Check this by finding the distance each walked, should be equal
C's walking time = 100 sec
5(120) = 600 ft
6(100) = 600 ft