Question 674695
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 10^x\ =\ 35]


Take the base 10 log of both sides.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log\left(10^x\right)\ =\ \log(35)]


Use


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_b(x^n)\ =\ n\log_b(x)]


to write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\log\left(10\right)\ =\ \log(35)]


Use


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_b(b)\ =\ 1]


to write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \log(35)]


From here it is just calculator work.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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