<PRE><B>Question 674515</B>
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*[tex \LARGE x\ -\ 3] is a factor of *[tex \LARGE p(x)] iff *[tex \LARGE p(3)\ =\ 0].


Substitute 3 for *[tex \LARGE x] in *[tex \LARGE p(x)] and do the arithmetic.  If you get zero, *[tex \LARGE x\ -\ 3] is a factor, otherwise not.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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