Question 60993
given a line containing (1,3),(2,4),(3,5)determine the slope-intercept from of the equation and give one additional point on this line and graph the function.
We need a slope and a point to make the equation of a line.
We don't have the slope, but we can find it using the slope formula:{{{highlight(m=(y2-y1)/(x2-x1))}}}, m=slope, (x1,y1) and (x2,y2) are given points.
Let (x1,y1)=(1,3) and (x2,y2)=(2,4)
{{{m=(4-3)/(2-1)}}}
{{{m=1/1}}}
{{{m=1}}} (I checked all the points, you can use any of them to get m=1)
We can now use the point slope equation to get the equation:{{{highlight(y-y1=m(x-x1))}}}, m=slope, and (x1,y1) is a given point.
m=1 and (x1,y1)=(1,3)
y-3=1(x-1)
y-3=x-1
y-3+3=x-1+3
y=x+2  <--this is slope intercept form {{{highlight(y=mx+b)}}}, m=slope and b=y-intercept.
:
You can find another point by letting x= a number, like 0 and solve for y.
y=0+2
y=2
Plot all these points and connect them and you should have this line:
{{{graph(300,200,-10,10,-10,10,x+2)}}}
Happy Calculating!!!