Question 674370
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Let *[tex \LARGE x] represent the number of Amy's sisters.  Let *[tex \LARGE y] represent the number of Amy's brothers.  Then Jason must have *[tex \LARGE x\ +\ 1] sisters, that is Amy's 3 sisters plus Amy herself.  Furthermore, Jason must have *[tex \LARGE y\ -\ 1] brothers since he can't be his own brother but *[tex \LARGE y] is the total number of boys.  All of the above presumes that there are no out of the ordinary ongoing transgender procedures amoung Amy, Jason, and all of their siblings. Hey, you never know these days.


Since Amy has as many sisters as brothers:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ y]


And since Jason has twice as many sisters as brothers:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(y\ -\ 1)\ =\ x\ +\ 1]


Substitute:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(x\ -\ 1)\ =\ x\ +\ 1]


Solve for *[tex \LARGE x] which is the number of boys since it is equal to *[tex \LARGE y] and then add 1 to get the number of girls.  Then add the number of boys to the number of girls.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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