Question 674291
x(3-x) + 2x(x-1)_<(less than or equal too).. x^2 - 3x + 12 


First, we need to use the distributive property on the left side of the equation. (x * 3) + (x * -x) + (2x * x) + (2x * -1) 

Which turns out to be...

{{{ 3x - x^2 + 2x^2 - 2x (is less than or equal to) x^2 - 3x + 12 }}}

Then, we need to get "x" on one side (I like "x" on the left side). Subtract "{{{ x^2 }}}" and add "{{{ 3x }}}" to both sides. 

We end up with...

4x (is less than or equal to) 12 

Divide both sides by "4," and we end up with...

x (is less than or equal to) 3