Question 674173


{{{5^(x^2-8x+12)=1}}}.....factor {{{(x^2-8x+12)=x^2-6x-2x+12=(x^2-6x)-(2x-12)=x(x-6)-2(x-6)=(x-2)(x-6)}}} and replace {{{1}}} with {{{5^0}}}


{{{5^((x-2)(x-6))=5^0}}}...same base, same exponents


{{{(x-2)(x-6)=0}}}

so, 

if {{{(x-2)=0}}}.->...{{{highlight(x=2)}}}

and

if {{{(x-6)=0}}}.->...{{{highlight(x=6)}}}