Question 60982
The line has equation {{{3y = x+10}}}
You want to get the line into a form {{{y = mx+b}}} where x is the slope and b is the place on the y-axis where the line crosses the y-axis.
Divide both sides of the equation by 3 and you get
{{{y = (1/3)x+(10/3)}}}
So, the slope of the line is {{{1/3}}}.

Any line parallel to this line will also have a slope of {{{1/3}}}.
So, we're looking for a line with equation {{{y = (1/3)x + b}}} and we need to figure out what b is.
We know that point (0,3) is on the parallel line so we know that when {{{x = 0}}} then {{{y = 3}}}. So, solve for b:

{{{3 = (1/3)*0 + b}}} or {{{3 = b}}}.
So, the equation of the parallel line is {{{y = (1/3)x +3}}}.