Question 673943
The problem is:
x 5 6
-------- + ------ - ------
x^2 -25 x+5 x 
:
Assume it is
{{{x/((x^2-25))}}} + {{{5/((x+5))}}} - {{{6/x}}}
Factor the 1st denominator as the "difference of squares
{{{x/((x-5)(x+5))}}} + {{{5/((x+5))}}} - {{{6/x}}}
the common denominator: x(x+5)(x-5)
{{{(x(x) + 5x(x-5) - 6(x-5)(x+5))/(x(x+5)(x-5))}}} = {{{(x^2 + 5x^2 - 25x - 6(x^2-25))/(x(x+5)(x-5))}}} = {{{(6x^2 - 25x - 6x^2 +150)/(x(x+5)(x-5))}}} =
{{{(-25x+150)/(x(x+5)(x-5))}}} = {{{-(25(x-6))/(x(x-5)(x+5))}}}