Question 673802

let {{{x}}},{{{x+1}}}, and {{{x+2}}} be three consecutive integers 

the sum of three consecutive integers is {{{-417}}}; so,

{{{x+(x+1)+(x+2)=-417}}}..solve for {{{x}}}

{{{x+x+1+x+2=-417}}}

{{{3x+3=-417}}}

{{{3x=-417-3}}}

{{{3x=-420}}}

{{{x=-420/3}}}


{{{highlight(x=-140)}}}.....first one


{{{x+1}}}...->...{{{-140+1}}}..->...{{{highlight(-139)}}}...second one

and 

{{{x+2}}}...->...{{{-140+2}}}..->...{{{highlight(-138)}}}...third one