Question 60945
Solve:
{{{5x^2+2x-1 = 0}}} Use the quadratic formula: {{{x = (-b+-sqrt(b^2-4ac))/2a}}}
{{{x = (-2+-sqrt(2^2-4(5)(-1)))/2(5)}}}
{{{x = (-2+-sqrt(4+20))/10}}}
{{{x = (-2+-sqrt(24))/10}}}
{{{x = (-2+2sqrt(6))/10}}} Simplify this to: {{{x = (-1+sqrt(6))/5}}}
{{{x = (-2-2sqrt(6))/10}}} Simplify this to: {{{x = (-1-sqrt(6))/5}}}