Question 673747

{{{(49a^2-b^2)/(7a-b)}}}...write {{{49}}} as {{{7^2}}}


{{{(7^2a^2-b^2)/(7a-b)}}}......now write {{{7^2a^2}}} as {{{(7a)^2}}}


{{{((7a)^2-b^2)/(7a-b)}}}.....now you have the difference of squares in nominator,us {{{a^2-b^2=(a-b)(a + b)}}} rule and factor it


{{{((7a-b)(7a+b))/(7a-b)}}}...now reduce


{{{(cross((7a-b))(7a+b))/cross((7a-b))}}}


{{{7a+b}}}.....the quotient