Question 60946
Write {{{15x^2 + 2x = 1 }}}
as {{{15x^2+2x-1 = 0}}}

This is a quadratic equation where {{{a=15}}},{{{b=2}}}, and {{{c=-1}}}

The discriminant, D = {{{b^2-4ac}}} = {{{2^2-4(15)(-1)}}} = {{{4+60}}} = {{{64}}}

64 is a positive perfect square so the equation has 2 distinct rational roots (since a, b and c are rational).