Question 673640
{{{(6x^3 - 7x^2 - 6x - 8)/(2x+3)}}}
...
2x+3 goes into {{{6x^3 - 7x^2}}}: {{{3x^2}}}
to get
{{{6x^3 + 9x^2}}}
subtracting
{{{6x^3 - 7x^2 - 6x^3 - 9x^2 = -16x^2}}}
...
2x+3 goes into {{{-16x^2 - 6x}}}: -8x
to get
{{{-16x^2-24x}}}
subtracting
{{{-16x^2 - 6x - -16x^2 - -24x = 18x}}}
...
2x+3 goes into 18x - 8: 9
to get
{{{18x + 27}}}
subtracting
{{{18x - 8 - 18x - 27 = -35}}}
...
{{{highlight_green((6x^3-7x^2-6x-8)/(2x+3) = 3x^2 - 8x + 9 - (35)/(2x+3))}}}
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