Question 673626
what is the point (x,y) on the unit circle that corresponds to a real number 23pi/6 ?
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Standard position of 23π/6 is in quadrant IV (24π/6-π/6)
The reference angle becomes &#960;/6 in quadrant IV where cos>0 and sin<0 
The x-coordinate represents the cos function and y-coordinate represents the sin function
On the unit circle, y/1=-1/2 at &#960;/6, so y=-1/2
Similarly, x/1=&#8730;3/2/1 at &#960;/6, so x=&#8730;3/2
The point (x,y) on the unit circle that corresponds to a real number 23pi/6 is: (&#8730;3/2,-1/2)
Check:
let A=reference angle &#960;/6  in quadrant IV
sin A=opp side/hypotenuse=y/1=-1/2/1=-1/2
cosA=adj side/hypotenuse=x/1=(&#8730;3/2)/1=&#8730;3/2