Question 673610
 Find x by solving for the system of equations using any method you prefer. 
    -8x + 4y = 9    and     3x = 4y + 6

Please help me ! 


-8x + 4y = 9 (Equ 1)

3x = 4y + 6 (Equ 2)


3x = 4y + 6 (Equ 2)

Subtract 4y from each side of the equation.

3x - 4y

4y + 6 - 4y

Combine like terms:

4y - 4y = 0

3x - 4y = 6 (Equ 3)

Add Equ 1 and Equ 3

-8x + 4y + 3x - 4y = 9 + 6

Combine like terms:

-8x + 3x = -5x

4y - 4y = 0

9 + 6 = 15

-5x = 15

Divide each side by -5

-5x/-5 = 15/-5

x = -3


Substitute x = -3 in Equ 3

3x - 4y = 6

3(-3) - 4y = 6

3(-3) = -9

-9 - 4y = 6

Add +9 to each side of the equation.

-9 - 4y + 9

6 + 9 = 15

Combine like terms:

-9 + 9 = 0

-4y = 15

Divide each side by -4

-4y/-4 = 15

y = -15/4


Check:

-8x + 4y = 9

-8(-3) + 4(-15/4) = 9

-8 * -3 = 24

4 * -15/4 = -60/4 = -15

24 - 15 = 9

9 = 9


Therefore;

x -3 and

y = -15/4




Lennox Obuong
Algebra 2 Student
Email: obuong3@aol.com