Question 673624
let investment in one of the fund is $x returned 6% interest, and investment in the other the fund is $(12000-x) returned 8% interest after one year. 
so the total interest =6*x/100+8*(12000-x)/100=880 (as per question)
or 6x+8(12000-x)=88000
or -2x=88000-96000=-8000
or x=4000

so 1st investment is 4000 at 6% & other is 8000 at 8%