Question 673552
Justin gets a head start of
{{{ 6*1.3 = 7.8 }}} mi
They are then {{{ 26 - 7.8 = 18.2 }}} mi apart
----------------
Let {{{ d }}} = the distance Rhonda now has 
to cover to meet Justin.
{{{ 18.2 - d }}} = distance Justin now has to cover
Let {{{ t }}} = the time it now takes them to meet
------------                    
After Justin's head start:
Justin's equation:
(1) {{{ 18.2 - d = 6t }}}
Rhonda's equation:
(2) {{{ d = 8t }}}
-------------
Substitute (2) into (1)
(1) {{{ 18.2 - 8t = 6t }}}
(1) {{{ 14t = 18.2 }}}
(1) {{{ t = 1.3 }}} hrs
and
(1) {{{ 18.2 - d = 6*1.3 }}}
(1) {{{ 18.2 - d = 7.8 }}}
(1) {{{ d = 18.2 - 7.8 }}}
(1) {{{ d = 10.4 }}}
Justin has been running for {{{ 1.3 + 1.3 = 2.6 }}} hrs
Rhonda travels {{{ d = 10.4 }}} mi from home
where they meet