Question 673555
Please help solve this equation *** It's not an equation.

Factor completely.

((( x^2q-q^3)))
Factor out 1
((( x^2q-q^3 = q*(x^2 - q^2))))
{{{x^2 - q^2)}}} is a difference of 2 squares.
{{{a^2 - b^2 = (a-b)*(a+b)}}}
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is the polynomial prime?
Obviously not, a q was factored out.