Question 673223
{{{49x^2 + 100 = 0}}}
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{{{49x^2 = -100}}}
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{{{sqrt(49x^2)}}} = +/- {{{sqrt(-100)}}}
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{{{sqrt(-100) = sqrt(-1*100) = (i)sqrt(100) = 10i}}}
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7x = +/- 10i
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x = +/- {{{10i/7}}}
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